.. I mistakenly assumed that adding every one of the upward forces and downward forces of The 2 masses along with the fulcrum would give me the correct response. So the upward drive (standard) exerted with the fulcrum will have to harmony the downward forces exerted by The 2 masses along with the fulcrum to ensure that the seesaw to get in equilibrium. Make sure you accurate me, if I'm Improper. Any help might be good. Many thanks.
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bijou1 reported: I mistakenly imagined that adding all of the upward forces and downward forces of the two masses along with the fulcrum would give me the right response. Unsure Whatever you indicate by that, but you experienced this equation
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four hundred lbs is how much the magnet can carry when trapped directly to iron. The amount of force you could crank out attracting or repelling it with an electromagnet is really only constrained by how big of an electromagnet you can also make and how powerful of a (non magnetic) construction you may make to hold every thing.
Making it absolutely free float is far more difficult. It fundamentally can’t be finished with just static magnets. You either want diamagnetic resources associated, or you would like some sort of Lively stabilization.
The traditional pressure is simply present When it comes to Every mass as a different cost-free physique. When you are attempting to find the response force at the fulcrum, the sum on the forces incorporates the burden from the beam and the weight of any masses resting on it. So when seeking to find the reactionary power (standard) exerted from the fulcrum, I need to begin to see the fulcrum as well as 2 masses resting on it as being a totally free entire body (free system of fulcrum) in its entirety.
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Making it no cost float is much harder. It effectively can’t be done with just static magnets. You possibly want diamagnetic materials associated, or you would like some type of active stabilization.
For those who go ahead and take seesaw together with the two masses as your (rigid) system then you can just sum the masses and have the equation over directly. Thank you a lot of! This clarified my questions about this issue.
The problem for rotational equilibrium in a seesaw challenge is once the sum of the clockwise torques is equal towards the sum of your counterclockwise torques. This means that the seesaw is well balanced and never rotating.